A) \[1.25\times {{10}^{19}}\]
B) \[6.25\times {{10}^{20}}\]
C) \[5.25\times {{10}^{19}}\]
D) \[2.55\times {{10}^{20}}\]
E) \[4.25\times {{10}^{20}}\]
Correct Answer: B
Solution :
\[I=4-0.08tA\] Or \[\frac{dq}{dt}=4-0.08tA\] Or \[q=\int_{0}^{50}{(4-0.08t)dt}C\] Or \[Ne=\left[ 4t-\frac{0.08{{t}^{2}}}{2} \right]_{0}^{50}=100C\] where N is number of electrons. or \[N=\frac{100}{e}=\frac{100}{1.6\times {{10}^{-19}}}\] \[=6.25\times {{10}^{20}}\]
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