A) \[{{F}_{2}}\]
B) \[H_{2}^{+}\]
C) \[{{N}_{2}}\]
D) \[O_{2}^{-}\]
E) \[{{B}_{2}}\]
Correct Answer: B
Solution :
\[H_{2}^{+}=\sigma 1{{s}^{1}}\] (According to molecular orbital theory) Bond order bonding electrons \[=\frac{-antibonding\text{ }electrons}{2}\] \[=\frac{1}{2}=0.5\] \[H_{2}^{+}\]is paramagnetic due to the presence of one unpaired electron.
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