| List - I | List - II |
| A. \[PC{{l}_{5}}\] | 1. Linear |
| B. \[I{{F}_{7}}\] | 2. Pyramidal |
| C. \[{{H}_{3}}{{O}^{+}}\] | 3. Trigonal bipyramidal |
| D. \[Cl{{O}_{2}}\] | 4. Tetrahedral |
| E. \[NH_{4}^{+}\] | 5. Pentagonal bipyramidal |
| 6. Angular |
A) A-3, B-5, C-2, D-1, E-4
B) A-3, B-5, C-4, D-1, E-2
C) A-3, B-5, C-6, D-1, E-2
D) A-3, B-5, C-2, D-6, E-4
E) A-3, B-5, C-2, D-4, E-1
Correct Answer: D
Solution :
\[PC{{l}_{5}}=s{{p}^{3}}d\] (Trigonal pyramidal) \[I{{F}_{7}}=s{{p}^{3}}{{d}^{3}}\] (Pentagonal bipyramidal) \[{{H}_{3}}{{O}^{+}}=s{{p}^{3}}\] (Pyramidal) \[Cl{{O}_{2}}=s{{p}^{2}}\] (Angular) bond length are shorter than single bond due to resonance. \[NH_{4}^{+}=s{{p}^{3}}\](Tetrahedral)
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