A) \[M{{n}^{2+}}\]
B) \[F{{e}^{2+}}\]
C) \[C{{r}^{2+}}\]
D) \[{{V}^{3+}}\]
E) \[C{{r}^{3+}}\]
Correct Answer: A
Solution :
Magnetic moment \[=\sqrt{n(n+2)}BM\] where\[n=\]number of unpaired electrons \[5.93=\sqrt{n(n+2)}\] \[n=5\] \[M{{n}^{2+}}\]ion\[(3{{d}^{5}})\] has 5 unpaired electrons and magnetic moment is 5.93 BM.
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