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CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2007

  • question_answer
    The number of roots of the equation \[|x|={{x}^{2}}+x-4\]is

    A)  4                                            

    B)  3                            

    C)  1                            

    D)         0

    E)  2

    Correct Answer: E

    Solution :

    The given equation is\[|x|={{x}^{2}}+x-4\] If \[x\ge 0,x={{x}^{2}}+x-4\] \[\Rightarrow \]\[{{x}^{2}}-4=0\Rightarrow x=\pm 2\] \[\therefore \]We take,\[x=2\](neglect\[x=-2\]) and if\[x<0\] \[-x={{x}^{2}}-x-4\] \[\Rightarrow \]               \[{{x}^{2}}=4\Rightarrow x=\pm 2\] \[\therefore \]We take\[x=-2\](neglect\[x=2\]) Thus, the number of roots of given equation is 2.


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