CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2007

  • question_answer
    The sets\[{{S}_{1}},{{S}_{2}},{{S}_{3}},....\]are given by \[{{S}_{1}}=\left\{ \frac{2}{1} \right\},\] \[{{S}_{2}}=\left\{ \frac{3}{2},\frac{5}{2} \right\},{{S}_{3}}=\left\{ \frac{4}{3},\frac{7}{3},\frac{10}{3} \right\},\] \[{{S}_{4}}=\left\{ \frac{5}{4},\frac{9}{4},\frac{13}{4},\frac{17}{4} \right\},....\] Then the sum of the numbers in the set\[{{S}_{25}}\]is

    A)  320                                       

    B)  322

    C)  324                       

    D)         325

    E)  326

    Correct Answer: E

    Solution :

    According to given pattern \[{{S}_{25}}=\left\{ \frac{26}{25},\frac{51}{25},\frac{76}{25},....upto\,25\,terms \right\}\] Here, \[a=\frac{26}{25},n=25,d=1\] \[\therefore \] \[{{S}_{25}}=\frac{25}{2}\left[ \frac{52}{25}+24 \right]=326\]


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