A) 1 A
B) 3 A
C) 10 mA
D) 30 A
E) 30 mA
Correct Answer: E
Solution :
Current for 50 divisions, \[{{I}_{g}}=\frac{1\times 50}{10}=5\,mA\] \[\therefore \] \[\frac{{{I}_{g}}}{I}=\frac{S}{S+G}\] \[\Rightarrow \] \[I=\left( \frac{S+G}{S} \right){{I}_{g}}\] Or \[I=\left( \frac{4+20}{4} \right)5mA=30\,mA\]
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