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CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2007

  • question_answer
    A square coil of side 25 cm having 1000 turns is rotated with a uniform speed in a magnetic field about an axis perpendicular to the direction of the field. At an instant t, the emf induced in the coil is\[e=200\text{ }sin\text{ }100\text{ }\pi t\]. The magnetic induction is

    A)  \[0.50\text{ }T\]                             

    B)  \[0.02\text{ }T\]             

    C)  \[{{10}^{-3}}T\]               

    D)         \[0.1\text{ }T\]

    E)  \[0.01\text{ }T\]

    Correct Answer: E

    Solution :

    \[e=200\,\sin \,100\pi t\] We have,                 \[{{e}_{0}}=200,\]                 \[\omega =100\,\pi \] \[\because \]     \[BAN\omega ={{e}_{0}}\] \[\therefore \]  \[B=\frac{{{e}_{0}}}{AN\omega }\]                 \[=\frac{200}{(0.25\times 0.25)\times 1000\times 100\pi }\] Or           \[B=0.01\,T\]


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