A) \[3\overset{\to }{\mathop{OM}}\,\]
B) \[4\overset{\to }{\mathop{OM}}\,\]
C) \[\overset{\to }{\mathop{OM}}\,\]
D) \[2\overset{\to }{\mathop{OM}}\,\]
E) \[\frac{1}{2}\overset{\to }{\mathop{OM}}\,\]
Correct Answer: B
Solution :
We know that the diagonals of a parallelogram bisect each other. Therefore, M is the mid point of AC and BD both. \[\therefore \] \[\overrightarrow{OA}+\overrightarrow{OC}=2\overrightarrow{OM}\text{ }and\text{ }\overrightarrow{OB}+\overrightarrow{OD}=2\overrightarrow{OM}\] \[\Rightarrow \] \[\overrightarrow{OA}+\overrightarrow{OB}+\overrightarrow{OC}+\overrightarrow{OD}=4\overrightarrow{OM}\]
You need to login to perform this action.
You will be redirected in
3 sec
