CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2007

  • question_answer
    If D, E and F are the mid points of the sides \[\overset{\to }{\mathop{BC}}\,,\text{ }\overset{\to }{\mathop{CA}}\,\] and\[\overset{\to }{\mathop{AB}}\,\]respectively of the triangle ABC and G is the centroid of the triangle, then \[\overset{\to }{\mathop{GD}}\,+\overset{\to }{\mathop{GE}}\,+\overset{\to }{\mathop{GF}}\,\]is

    A)  \[\overset{\to }{\mathop{O}}\,\]           

    B)        \[2\overset{\to }{\mathop{AB}}\,\]

    C)  \[2\overset{\to }{\mathop{GE}}\,\]                      

    D)        \[2\overset{\to }{\mathop{GC}}\,\]

    E)  \[\overset{\to }{\mathop{GA}}\,+\overset{\to }{\mathop{GB}}\,\]

    Correct Answer: A

    Solution :

    Since, D, E and F are mid points of the sides\[\overrightarrow{BC},\overrightarrow{CA}\] and\[\overrightarrow{AB}\]respectively of the triangle ABC and G is the centroid of the triangle, Thus, G will also be centroid of\[\Delta DEF\]. Hence,\[\overrightarrow{GD}+\overrightarrow{GE}+\overrightarrow{GF}=\overrightarrow{GA}+\overrightarrow{GB}+\overrightarrow{GC}\] \[\overrightarrow{GA}+2\overrightarrow{GD}\] \[\overrightarrow{GA}-\overrightarrow{GA}=\overrightarrow{0}\] (\[\because \]G divides AC in the ratio\[2:1\])


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