CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2007

  • question_answer
    If\[P(x,y,z)\]is a point on the line segment joining Q (2, 2, 4) and R (3, 5, 6) such that projections of\[\overrightarrow{OP}\]on the axes are\[\frac{13}{5},\frac{19}{5},\frac{26}{5}\]respectively, then P divides QR in the ratio

    A)  1 : 2                                      

    B)  3 : 2

    C)  2 : 3                      

    D)         1 : 3

    E)  3 : 1

    Correct Answer: B

    Solution :

    Since,\[\overrightarrow{OP}\]has projections\[\frac{13}{5},\frac{19}{5}\]and\[\frac{26}{5}\]on the coordinate axes, therefore \[\overrightarrow{OP}=\frac{13}{5}\hat{i}+\frac{19}{5}\hat{j}+\frac{26}{5}\hat{k}\]. Suppose P divides the line joining Q(2, 2, 4) and R (3, 5, 6) in the ratio\[\lambda :1\]. Then, the position vector of\[P\]is \[\left( \frac{3\lambda +2}{\lambda +1} \right)\hat{i}+\left( \frac{5\lambda +2}{\lambda +1} \right)\hat{j}+\left( \frac{6\lambda +4}{\lambda +1} \right)\hat{k}\] \[\therefore \] \[\frac{13}{5}i+\frac{19}{5}\hat{j}+\frac{26}{6}\hat{k}=\left( \frac{3\lambda +2}{\lambda +1} \right)\hat{i}\]                                 \[+\left( \frac{5\lambda +2}{\lambda +1} \right)\hat{j}\left( \frac{6\lambda +4}{\lambda +1} \right)\hat{k}\] \[\Rightarrow \] \[\frac{3\lambda +2}{\lambda +1}=\frac{13}{5},\frac{5\lambda +2}{\lambda +1}=\frac{19}{5}\] And        \[\frac{6\lambda +4}{\lambda +1}=\frac{26}{5}\] \[\Rightarrow \]               \[2\lambda =3\Rightarrow \lambda =\frac{3}{2}\] Hence, P divides QR in the ratio\[3:2\].


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