A) \[200{{s}^{-1}}\]
B) \[100{{s}^{-1}}\]
C) \[300{{s}^{-1}}\]
D) \[250{{s}^{-1}}\]
E) \[150{{s}^{-1}}\]
Correct Answer: A
Solution :
Frequency of second overtone (fifth harmonic) of closed pipe\[=\frac{5v}{4l}\]. Frequency of first overtone (second harmonic) of open pipe\[=\frac{2v}{2l}\] Accordingly, \[\frac{5v}{4l}-\frac{2v}{2l}=100\] Or \[\frac{v}{4l}=100\] Or \[v=400\,l\] Fundamental frequency of open pipe \[=\frac{v}{2l}=\frac{400l}{2l}=200{{s}^{-1}}\]
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