A) \[11.4\Omega ,17.5A\]
B) \[30.7\Omega ,6.5A\]
C) \[40.4\,\Omega ,\,5\,A\]
D) \[50\text{ }\Omega ,\text{ }4\text{ }A\]
E) \[35\text{ }\Omega ,6.5\text{ }A\]
Correct Answer: D
Solution :
\[{{Z}^{2}}={{R}^{2}}+{{(2\pi fL)}^{2}}\] \[={{(30)}^{2}}+{{\left( 2\pi \times 50\times \frac{0.4}{\pi } \right)}^{2}}\] \[=(900+1600)=2500\] Or \[Z=50\,\Omega \] Also, \[I=\frac{V}{Z}=\frac{200}{50}=4A\]
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