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CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2007

  • question_answer
    A missile is fired from the ground level rises\[x\]metres vertically upwards in t seconds where\[x=100t-\frac{25}{2}{{t}^{2}}.\]The maximum height reached is

    A)  200m                                   

    B)  125m

    C)  160m                   

    D)         190m

    E)  300m

    Correct Answer: A

    Solution :

    The given equation is \[x=100t-\frac{25}{2}{{t}^{2}}\] On differentiating w.r.t.\[x,\]we get                 \[\frac{dx}{dt}=100-\frac{25}{2}.(2t)=100-25t\] We know that the velocity of missile is zero at maximum height. \[\therefore \]On putting\[\frac{dx}{dt}=0,\]we get \[100-25t=0\] \[\Rightarrow \]               \[t=4\] \[\therefore \]\[x=100\times 4-\frac{25\times 16}{2}=400-200\] \[=200m\]


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