A) 6s
B) 5s
C) 4s
D) 12s
E) 10s
Correct Answer: A
Solution :
\[s=ut+\frac{1}{2}g{{t}^{2}}\] \[\therefore \] \[30=-25t+\frac{10}{2}{{t}^{2}}\] or \[{{t}^{2}}-5t-6=0\] or \[(t-6)(t+1)=0\] \[\therefore \] \[t=6\,s\]
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