CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2007

  • question_answer
    A simple pendulum is released from A as shown. If m and I represent the mass of the bob and length of the pendulum, the gain in kinetic energy at B is

    A)  \[\frac{mgl}{2}\]                             

    B)  \[\frac{mgl}{\sqrt{2}}\]

    C)         \[\frac{\sqrt{3}}{2}mgl\]             

    D)         \[\frac{2}{\sqrt{3}}mgl\]

    E)  \[mgl\]

    Correct Answer: C

    Solution :

    Loss of potential energy in coming from A to \[B=mgh\] \[=mgl\,cos30{}^\circ \]                 \[=\frac{\sqrt{3}}{2}mgl\] Kinetic energy gained = loss of potential energy                 \[=\frac{\sqrt{3}}{2}mgl\]


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