A) 3h
B) 1.5 h
C) 6h
D) 4h
E) 2h
Correct Answer: B
Solution :
As angular momentum is conserved, so \[I\omega =constant\] \[\therefore \] \[{{I}_{2}}{{\omega }_{2}}={{I}_{1}}{{\omega }_{1}}\] Or \[\frac{2}{5}M{{\left( \frac{R}{4} \right)}^{2}}\times \frac{2\pi }{T}=\frac{2}{5}M{{R}^{2}}\times \frac{2\pi }{24}\] Or \[16T=24\] \[\Rightarrow \] \[T=1.5h\]
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