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CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2007

  • question_answer
    The activation energy of exothermic reaction \[A\to B\] is\[80\text{ }kJ\text{ }mo{{l}^{-1}}\]. The heat of reaction is\[200\text{ }kJ\text{ }mo{{l}^{-1}}\]. The activation energy for the reaction\[B\to A\]\[(in\text{ }kJ\text{ }mo{{l}^{-1}})\]will be

    A)  80  

    B)                                         120

    C)  40                         

    D)         200

    E)  280

    Correct Answer: E

    Solution :

    \[{{E}_{a}}\] (activation energy) \[(A\to B)=80\text{ }kJ\text{ }mo{{l}^{-1}}\] Heat of reaction\[(A\to B)=200\text{ }kJ\text{ }mo{{l}^{-1}}\] for\[(B\to A)\]backward reaction \[{{E}_{a}}(B\to A)={{E}_{a}}(A\to B)+\]heat of reaction \[=80+200=280\,kJ\,mo{{l}^{-1}}\]


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