A) 8 mm
B) 6 mm
C) 4 mm
D) 12 mm
E) 10 mm
Correct Answer: E
Solution :
Original capacity, with air \[C=\frac{{{\varepsilon }_{0}}A}{d}\] When dielectric plate (medium) of thickness t is introduced between the plates, then capacity becomes \[C=\frac{{{\varepsilon }_{0}}A}{d-t\left( 1-\frac{1}{K} \right)}\] but as given,\[C=C\] \[\therefore \] \[\frac{{{\varepsilon }_{0}}A}{d}=\frac{{{\varepsilon }_{0}}A}{d-t\left( 1-\frac{1}{K} \right)}\] Or \[d=d-t+\frac{t}{K}\] Or \[8=d-4+\frac{4}{2}\] Or \[8=d-2\] Or \[d=10\,mm\]
You need to login to perform this action.
You will be redirected in
3 sec
