A) \[CoC{{l}_{3}}.4N{{H}_{3}}\,and\,PtC{{l}_{4}}.4N{{H}_{3}}\]
B) \[CoC{{l}_{3}}.3N{{H}_{3}}\,and\,PtC{{l}_{4}}.5N{{H}_{3}}\]
C) \[CoC{{l}_{3}}.6N{{H}_{3}}\,and\,PtC{{l}_{4}}.5N{{H}_{3}}\]
D) \[CoC{{l}_{3}}.6N{{H}_{3}}\,and\,PtC{{l}_{4}}.3N{{H}_{3}}\]
E) \[CoC{{l}_{3}}.5N{{H}_{3}}\,and\,PtC{{l}_{4}}.6N{{H}_{3}}\]
Correct Answer: C
Solution :
\[C{{o}^{3+}}\]and\[P{{t}^{4+}}=6\]coordination number \[CoC{{l}_{3}}.6N{{H}_{3}}\]and \[PtC{{l}_{4}}.5N{{H}_{3}}\] \[[Co{{(N{{H}_{3}})}_{6}}]C{{l}_{3}}\xrightarrow[{}]{In\text{ }solution}\] \[{{[Co{{(N{{H}_{3}})}_{6}}]}^{3+}}+3C{{l}^{-}}\] \[[PtCl{{(N{{H}_{3}})}_{5}}]C{{l}_{3}}\xrightarrow[{}]{In\text{ }solution}\] \[{{[PtCl{{(N{{H}_{3}})}_{5}}]}^{3+}}+3C{{l}^{-}}\] Number of ionic species are same in the solution of both complexes, therefore their equimolar solutions will show same conductance.
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