A) \[N{{H}_{4}}OH/80{}^\circ C\]
B) cone. \[{{H}_{2}}S{{O}_{4}}/160{}^\circ C\]
C) Anhydrous \[ZnC{{l}_{2}}/150{}^\circ C\]
D) Dilute \[HCl/THF,\,80{}^\circ C\]
E) \[C{{H}_{3}}OK/160-200{}^\circ C\]
Correct Answer: E
Solution :
\[CH\equiv CH+C{{H}_{3}}OH\xrightarrow[160-200{}^\circ C]{C{{H}_{3}}OK}\] \[\underset{methyl\text{ }vinyl\text{ }ether}{\mathop{C{{H}_{3}}O-CH=C{{H}_{2}}}}\,\]
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