A) n-butyl alcohol
B) sec-butyl alcohol
C) acetophenone
D) acetaldehyde
E) ethylmethyl ketone
Correct Answer: A
Solution :
lodoform test is given by the compounds containing \[C{{H}_{3}}CO\]group or \[C{{H}_{3}}\overset{|}{\mathop{C}}\,HOH\] group. \[C{{H}_{3}}CHO+3{{I}_{2}}+3\text{ }NaOH\to \] \[\underset{\begin{smallmatrix} (yellow\text{ }ppt) \\ \,\,\,\,iodoform \end{smallmatrix}}{\mathop{CH{{I}_{3}}+}}\,HCOONa+3NaI+3{{H}_{2}}O\] \[\because \] n butyl alcohol\[(C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}OH)\] does not give iodoform test because it does not possess the\[C{{H}_{3}}CO\]or\[C{{H}_{3}}\overset{|}{\mathop{C}}\,HOH\]group.
You need to login to perform this action.
You will be redirected in
3 sec
