A) \[[Cr{{({{H}_{2}}O)}_{5}}Cl]B{{r}_{2}};[Cr{{({{H}_{2}}O)}_{4}}B{{r}_{2}}]Cl.{{H}_{2}}O\]
B) \[[Cr{{({{H}_{2}}O)}_{5}}Cl]B{{r}_{2}};[Cr{{({{H}_{2}}O)}_{3}}ClB{{r}_{2}}.2{{H}_{2}}O]\]
C) \[[Cr{{({{H}_{2}}O)}_{5}}Br]BrCl;[Cr{{({{H}_{2}}O)}_{4}}ClBr]Br.{{H}_{2}}O\]
D) \[[Cr{{({{H}_{2}}O)}_{5}}Cl]B{{r}_{2}};[Cr{{({{H}_{2}}O)}_{4}}ClBr]Br.{{H}_{2}}O\]
E) \[[Cr{{({{H}_{2}}O)}_{4}}B{{r}_{2}}]Cl.{{H}_{2}}O;[Cr{{({{H}_{2}}O)}_{5}}Cl]B{{r}_{2}}\]
Correct Answer: E
Solution :
One mole of X gave depression corresponding to 2 moles of particles, ie., on ionization X gives 2 moles of ions, thus it contains only one ion outside the coordination sphere and its structural formula is\[[Cr{{({{H}_{2}}O)}_{4}}B{{r}_{2}}]Cl.{{H}_{2}}O\] While Y gives 3 moles of ions, so it contains two ions outside the coordination sphere and its structural formula is\[[Cr{{({{H}_{2}}O)}_{5}}Cl]B{{r}_{2}}\] \[[Cr{{({{H}_{2}}O)}_{4}}B{{r}_{2}}]Cl.{{H}_{2}}O\xrightarrow[{}]{ionisation}\] \[\underbrace{{{[Cr{{({{H}_{2}}O)}_{4}}B{{r}_{2}}]}^{+}}+C{{l}^{-}}}_{2\,ions}+{{H}_{2}}O\] \[[Cr{{({{H}_{2}}O)}_{5}}Cl]B{{r}_{2}}\xrightarrow{ionisation}\underbrace{{{[Cr{{({{H}_{2}}O)}_{5}}Cl]}^{2+}}+2B{{r}^{-}}}_{3\,ions}\]
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