2. Solved Papers
  3. CEE Kerala Engineering

CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2008

  • question_answer
    Suppose that two persons A and B solve the equation\[{{x}^{2}}+ax+b=0\]. While solving A commits a mistake in the coefficient of\[x\]was taken as 15 in place of-9 and finds the roots as \[-7\]and\[-2\]. Then, the equation is

    A)  \[{{x}^{2}}+9x+14=0\]

    B)  \[{{x}^{2}}-9x+14=0\]

    C)  \[{{x}^{2}}+9x-14=0\]

    D)  \[{{x}^{2}}-9x-14=0\]

    E)  None of the above

    Correct Answer: B

    Solution :

    Let the incorrect equation is \[{{x}^{2}}+15x+b=0\]. Since, roots are\[-7\]and\[-2\]. \[\therefore \]Product of roots, \[b=14\] So, correct equation is \[{{x}^{2}}-9x+14=0\]


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