A) 1.123
B) 0.0891
C) 1.414
D) 0.414
E) 1.732
Correct Answer: A
Solution :
Given \[{{r}_{N{{a}^{+}}}}/{{r}_{C{{l}^{-}}}}=0.55\] \[{{r}_{{{K}^{+}}}}/{{r}_{C{{l}^{-}}}}=0.74\] \[\frac{{{r}_{KCl}}}{{{r}_{NaCl}}}=?\] \[\frac{{{r}_{N{{a}^{+}}}}}{{{r}_{C{{l}^{-}}}}}=0.55\] \[\frac{{{r}_{N{{a}^{+}}}}}{{{r}_{C{{l}^{-}}}}}+1=0.55+1\] \[\frac{r_{Na}^{+}+{{r}_{C{{l}^{-}}}}}{{{r}_{C{{l}^{-}}}}}=1.55\] ?? (i) \[\frac{{{r}_{{{K}^{+}}}}}{{{r}_{C{{l}^{-}}}}}=0.74\] \[\frac{{{r}_{{{K}^{+}}}}}{{{r}_{C{{l}^{-}}}}}+1=0.74+1\] \[\frac{{{r}_{{{K}^{+}}}}+{{r}_{C{{l}^{-}}}}}{{{r}_{C{{l}^{-}}}}}=1.74\] ?.. (ii) Eqs (ii)/(i) \[\frac{{{r}_{{{K}^{+}}}}+{{r}_{C{{l}^{-}}}}}{{{r}_{N{{a}^{+}}}}+{{r}_{C{{l}^{-}}}}}=\frac{1.74}{1.55}=1.1226\]You need to login to perform this action.
You will be redirected in
3 sec