A) \[25x+25y-1=0\]
B) \[5x-5y+3=0\]
C) \[25x+25y-4=0\]
D) \[25x-25y+6=0\]
E) \[5x-5y+7=0\]
Correct Answer: C
Solution :
Equation of intersection of lines is \[(100x+50y-1)+\lambda (75x+25y+3)=0\] \[\Rightarrow \]\[(100+75\lambda )x+(50+25\lambda )y=1-3\lambda \]?..(i) \[\Rightarrow \] \[\frac{x}{\frac{1-3\lambda }{100+75\lambda }}+\frac{y}{\frac{1-3\lambda }{50+25\lambda }}=1\] According to the given condition \[\frac{1-3\lambda }{100+75\lambda }=\frac{1-3\lambda }{50+25\lambda }\] \[\Rightarrow \] \[50=-50\lambda \Rightarrow \lambda =-1\] \[\therefore \]From Eq. (i), \[25x+25y-4=0\]
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