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  3. CEE Kerala Engineering

CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2008

  • question_answer
    Equation of the directrix of the conic \[{{x}^{2}}+4y+4=0\]is

    A)  \[y=1\]               

    B)  \[y=-1\]

    C)  \[y=0\]

    D)         \[x=0\]

    E)  \[x=1\]

    Correct Answer: C

    Solution :

    Given equation can be rewritten as \[{{x}^{2}}=-4(y+1)\] \[\Rightarrow \]\[{{X}^{2}}=-4Y,\]where\[X=x\]and\[y=y+1\] Equation of directrix is\[Y=1\] \[\therefore \]  \[y+1=1\] \[\Rightarrow \]               \[y=0\]


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