CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2008

  • question_answer
    An object of mass 5 kg is attached to the hook of a spring balance and the balance is suspended vertically from the roof of a lift. The reading on the spring balance when the lift is going up with an acceleration of 0.25 \[m{{s}^{-2}}\]is \[(g=10\text{ }m{{s}^{-2}})\]

    A)  51.25 N               

    B)         48.75 N               

    C)         52.75 N               

    D)         47.25 N

    E)  55 N

    Correct Answer: A

    Solution :

    On moving upward,             weight, \[w=(mg+a)=5(10+0.25)\] \[=5\times 10.25\]                      \[=51.25N\]


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