CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2008

  • question_answer
    A particle acted upon by constant forces \[4\hat{i}+\hat{j}-3\hat{k}\] and\[3\hat{i}+\hat{j}-\hat{k}\]is displaced from the point\[\hat{i}+2\hat{j}+3\hat{k}\]to the, point\[5\hat{i}+4\hat{j}+\hat{k}\]. The total work done by the forces in SI unit is

    A)  20                         

    B)         40                         

    C)  50                         

    D)         30

    E)  35

    Correct Answer: B

    Solution :

    Work done, \[W=\overrightarrow{F}.d\overrightarrow{s}\] \[=({{\overrightarrow{F}}_{1}}+{{\overrightarrow{F}}_{2}}).({{\overrightarrow{s}}_{2}}-{{\overrightarrow{s}}_{1}})\] \[=\{(4\hat{i}+\hat{j}-3\hat{k})+(3\hat{i}+\hat{j}-\hat{k})\}\]                 \[\{(5\hat{i}+4\hat{j}+\hat{k})-(\hat{i}+2\hat{j}+3\hat{k})\}\] \[=(7\hat{i}+2\hat{j}-4\hat{k}).(4\hat{i}+2\hat{j}-2\hat{k})\] \[=28+4+8=40\text{ }J\]


You need to login to perform this action.
You will be redirected in 3 sec spinner