A) 1.41
B) 1.5
C) 1.6
D) 1.33
E) 1.73
Correct Answer: E
Solution :
\[\mu =\frac{\sin \left( \frac{A+{{\delta }_{m}}}{2} \right)}{\sin \frac{A}{2}}\] For equilateral prism, \[\angle A=60{}^\circ \] \[\therefore \]\[\mu =\frac{\sin \left( \frac{60{}^\circ +60{}^\circ }{2} \right)}{\sin \left( \frac{60{}^\circ }{2} \right)}=\frac{\sin 60{}^\circ }{\sin 30{}^\circ }=\frac{\frac{\sqrt{3}}{2}}{\frac{1}{2}}\] \[=\sqrt{3}=1.73\]
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