CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2008

  • question_answer
    A particle is moving under the influence of a force given by\[F=kx,\]where k is a constant and\[x\]is the distance moved. The energy (in joules) gained by the particle in moving from \[x=0\]to\[x=3\]is

    A)  2k                         

    B)         3.5 k     

    C)         4.5 k                     

    D)         9k

    E)  9.5 k

    Correct Answer: C

    Solution :

    \[U=\frac{1}{2}k(x_{2}^{2}-x_{1}^{2})\] \[=\frac{1}{2}k({{3}^{2}}-{{0}^{2}})\] \[=\frac{9}{2}k=4.5\,k\]


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