A) \[3\times {{10}^{8}}m/s\]
B) \[1.34\times {{10}^{8}}m/s\]
C) \[2.25\times {{10}^{8}}m/s\]
D) \[2.5\times {{10}^{8}}m/s\]
E) \[2.75\times {{10}^{8}}m/s\]
Correct Answer: C
Solution :
\[\frac{Speed\text{ }of\text{ }light\text{ }in\text{ }air}{Speed\text{ }of\text{ }light\text{ }in\text{ }aqueous\text{ }humor}\] \[=\frac{Wavelength\text{ }of\text{ }light\text{ }in\text{ }air}{Wavelength\text{ }of\text{ }light\text{ }in\text{ }aqueous\text{ }humor}\] \[\Rightarrow \] \[\frac{{{v}_{1}}}{{{v}_{2}}}=\frac{{{\lambda }_{1}}}{{{\lambda }_{2}}}\] Or \[{{v}_{2}}=\frac{{{\lambda }_{2}}}{{{\lambda }_{1}}}\times {{v}_{1}}=\frac{474}{633}\times 3\times {{10}^{8}}\] \[=2.25\times {{10}^{8}}m/s\]
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