A) 0.4 J of work is done by the gas from A to B.
B) 0.2 J of work is done on the gas from C and D.
C) No work is done by the gas from B to C.
D) Net work done by the gas in one cycle is 0.2 J.
E) Work is done by the gas in going from B to C and on the gas from D to A.
Correct Answer: E
Solution :
The area under p-V diagram = work done or \[W=AD\times DC\] \[=(2\times 1.05-1\times {{10}^{5}})\text{ }N{{m}^{-2}}\times (4-2)\times {{10}^{-6}}{{m}^{3}}\] \[=1\times {{10}^{5}}\times 2\times {{10}^{-6}}J=0.2J\] Therefore, 0.2 J work is done by the gas in going from B to C and on the gas from D to A.
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