A) \[{{E}_{y}}=33\,\cos \pi \times {{10}^{11}}\left( t-\frac{x}{c} \right),\] \[{{B}_{z}}=1.1\times {{10}^{-7}}\cos \pi \times {{10}^{11}}\left( t-\frac{x}{c} \right)\]
B) \[{{E}_{y}}=11\,\cos 2\pi \times {{10}^{11}}\left( t-\frac{x}{c} \right),\] \[{{B}_{y}}=11\times {{10}^{-7}}\cos 2\pi \times {{10}^{11}}\left( t-\frac{x}{c} \right)\]
C) \[{{E}_{x}}=33\,\cos \pi \times {{10}^{11}}\left( t-\frac{x}{c} \right),\] \[{{B}_{x}}=11\times {{10}^{-7}}\cos \pi \times {{10}^{11}}\left( t-\frac{x}{c} \right)\]
D) \[{{E}_{y}}=66\,\cos 2\pi \times {{10}^{11}}\left( t-\frac{x}{c} \right),\] \[{{B}_{z}}=2.2\times {{10}^{-7}}\cos 2\pi \times {{10}^{11}}\left( t-\frac{x}{c} \right)\]
E) \[{{E}_{y}}=66\,\cos \pi \times {{10}^{11}}\left( t-\frac{x}{c} \right),\] \[{{B}_{y}}=2.2\times {{10}^{-7}}\,\cos \pi \times {{10}^{11}}\left( t-\frac{x}{c} \right)\]
Correct Answer: D
Solution :
The equation of electric field occurring in Y-direction \[{{E}_{y}}=66\,\cos 2\pi \times {{10}^{11}}\left( t-\frac{x}{c} \right)\] Therefore, for the magnetic field in Z-direction \[{{B}_{z}}=\frac{{{E}_{y}}}{c}\left( \frac{600}{3\times {{10}^{8}}} \right)\cos 2\pi \times {{10}^{11}}\left( t-\frac{x}{c} \right)\] \[=22\times {{10}^{-8}}\cos 2\pi \times {{10}^{11}}\left( t-\frac{x}{c} \right)\] \[=2.2\times {{10}^{-7}}\cos 2\pi \times {{10}^{11}}\left( t-\frac{x}{c} \right)\]
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