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CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2009

  • question_answer
    0.25 g of an organic compound on Kjeldahls analysis gave enough ammonia to just neutralize \[10\text{ }c{{m}^{3}}\]of\[0.5\text{ }M\text{ }{{H}_{2}}S{{O}_{4}}\]. The percentage of nitrogen in the compound is

    A) 28  

    B)                                        56

    C)  14                         

    D)        112

    E) 42

    Correct Answer: B

    Solution :

    From Kjeldahls method, Per cent of nitrogen\[=\frac{1.4\times N\times V}{W}\]                                 \[=\frac{1.4\times 0.5\times 2\times 10}{0.25}\] \[=56%\]


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