A) det\[({{A}^{-1}})\]
B) det\[({{B}^{-1}})\]
C) \[\det \,(B)\]
D) \[\det \,(A)\]
E) det \[(A{{B}^{-1}})\]
Correct Answer: D
Solution :
Given, \[A={{B}^{-1}}AB\] \[\Rightarrow \] \[BA=AB\] \[\therefore \] \[\det ({{B}^{-1}}AB)=\det ({{B}^{-1}}BA)\] \[=\det (A)\]You need to login to perform this action.
You will be redirected in
3 sec