A) \[3I\]
B) \[I\]
C) \[-I\]
D) \[-2I\]
E) \[2I\]
Correct Answer: B
Solution :
Given, \[A=\left| \begin{matrix} 1 & 0 & 0 \\ x & 1 & 0 \\ x & x & 1 \\ \end{matrix} \right|\Rightarrow A=1\] \[\therefore \] \[{{A}^{3}}-4{{A}^{2}}+3A+I={{(1)}^{3}}-4{{(1)}^{3}}+3(1)+I\] \[=I\]You need to login to perform this action.
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