A) ethanamide
B) N-methylethanamide
C) N, N-dimethylethanamide
D) phenylmethanamide
E) butanamide
Correct Answer: B
Solution :
Secondary amides such as N-methylethanamide on reduction with\[LiAl{{H}_{4}}\]give secondary amines. \[\underset{N\text{ }-methylethanamide}{\mathop{C{{H}_{3}}CONHC{{H}_{3}}}}\,+[H]\xrightarrow{LiAl{{H}_{4}}}\] \[\underset{2{}^\circ \text{ }amine}{\mathop{C{{H}_{3}}C{{H}_{2}}NHC{{H}_{3}}}}\,+{{H}_{2}}O\]
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