A) \[45\text{ }J\]
B) \[30\text{ }J\]
C) \[70\text{ }J\]
D) \[135\text{ }J\]
E) \[20\text{ }J\]
Correct Answer: A
Solution :
Work done = area between the force displacement graph \[W=\frac{1}{2}\times 6\times 10-5\times 4+5\times 4-5\times 2\] \[W=20\,J\] According to work-energy theorem \[K{{E}_{f}}=W+\Delta K\] \[=20+25\] \[=455\,J\]
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