A) \[{{x}^{2}}+4x-8y+12=0\]
B) \[{{x}^{2}}-4x-8y+12=0\]
C) \[{{y}^{2}}-8x-4y+12=0\]
D) \[{{y}^{2}}+4y-8x+12=0\]
E) \[{{y}^{2}}-8x-2y-17=0\]
Correct Answer: C
Solution :
Given, F(3, 2) and V(1, 2). Here, we see that y-coordinates are same, it means that axis of the parabola is parallel to \[x-\]axis. Here, \[a=3-1=2\] \[\therefore \]Required equation of parabola is \[{{(y-2)}^{2}}=4\times 2(x-1)\] \[\Rightarrow \] \[{{y}^{2}}-4y-8x+12=0\]
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