CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2009

  • question_answer
    A system consists of 3 particles each of mass m located at points (1, 1), (2, 2) and (3, 3). The coordinates of the centre of mass are

    A)  (6, 6)             

    B)         (3, 3)

    C)  (1, 1)                    

    D)         (2, 2)

    E)  (5, 5)

    Correct Answer: D

    Solution :

    If 3 masses are equal ie, \[{{m}_{1}}={{m}_{2}}={{m}_{3}}\] then coordinate of the centre of mass \[(x,y)=\left[ \frac{{{m}_{1}}{{x}_{1}}+{{m}_{2}}{{x}_{2}}+{{m}_{3}}{{x}_{3}}}{{{m}_{1}}+{{m}_{2}}+{{m}_{3}}}, \right.\] \[\left. \frac{{{m}_{1}}{{y}_{1}}+{{m}_{2}}{{y}_{2}}+{{m}_{3}}{{y}_{3}}}{{{m}_{1}}+{{m}_{2}}+{{m}_{3}}} \right]\] \[=\left[ \frac{m+2m+3m}{3m},\frac{m+2m+3m}{3m} \right]\] \[=\left[ \frac{6m}{3m},\frac{6m}{3m} \right]\] \[=[2,2]\]            


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