2. Solved Papers
  3. CEE Kerala Engineering

CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2009

  • question_answer
    The equation of the tangent to the curve \[{{x}^{2}}-2xy+{{y}^{2}}+2x+y-6=0\]at (2, 2) is

    A)  \[2x+y-6=0\]    

    B)         \[2y+x-6=0\]

    C)  \[x+3y-8=0\]    

    D)        \[3x+y-8=0\]

    E)  \[x+y-4=0\]

    Correct Answer: A

    Solution :

    Given,\[{{x}^{2}}-2xy+{{y}^{2}}+2x+y-6=0\] On differentiating w.r.t.\[x,\]we get \[2x-2\left( y+x\frac{dy}{dx} \right)+2y\frac{dy}{dx}+2\frac{dy}{dx}=0\] At (2, 2), \[4-2\left( 2+2\frac{dy}{dx} \right)+4\frac{dy}{dx}+2+\frac{dy}{dx}=0\] \[\Rightarrow \]               \[\frac{dy}{dx}=-2\] \[\therefore \]Equation of tangent at (2, 2) is \[(y-2)=-2(x-2)\] \[\Rightarrow \]               \[2x+y=6\]


You need to login to perform this action.
You will be redirected in 3 sec spinner