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CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2009

  • question_answer
    If\[{{a}_{1}}=1\]and\[{{a}_{n}}=n{{a}_{n-1}}\]for all positive integer\[n>2,\]then\[{{a}_{5}}\]is equal to

    A)  125       

    B)                                         120

    C)  100                       

    D)         24

    E)  6

    Correct Answer: B

    Solution :

    Given, \[{{a}_{n}}=n{{a}_{n-1}}\] For \[n=2\] \[{{a}_{2}}=2{{a}_{1}}=2\]               (\[\because \]\[{{a}_{1}}=1\]given) \[{{a}_{3}}=3{{a}_{2}}=3(2)=6\] \[{{a}_{4}}=4({{a}_{3}})=4(6)=24\] \[\therefore \]  \[{{a}_{5}}=5({{a}_{4}})=5(4)=120\]


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