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CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2009

  • question_answer
    An observer is approaching a stationary source with a velocity\[\frac{1}{4}\]th of the velocity of sound. Then the ratio of the apparent frequency to actual frequency of source is

    A)  \[4:5\]                 

    B)         \[5:4\]

    C)  \[2:3\]                 

    D)         \[3:2\]

    E)  \[2:5\]

    Correct Answer: B

    Solution :

    When an observer is moving towards the source apparent frequency \[n=n\times \left( \frac{{{v}_{1}}+{{v}_{o}}}{v} \right)\] Or           \[n=n\times \left( \frac{v+v/4}{v} \right)\] Or           \[n=n\times \frac{5}{4}\] Or           \[\frac{n}{n}=\frac{5}{4}\]


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