CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2009

  • question_answer
    When a wave travels in a medium, the particle displacement is given by the equation\[y=a\sin 2\pi (bt-cx)\]where a, b and c are constants. The maximum particle velocity will be twice the wave velocity, if

    A)  \[c=\frac{1}{\pi a}\]      

    B)         \[c=\pi a\]

    C)  \[b=ac\]             

    D)         \[b=\frac{1}{ac}\]

    E)  \[a=bc\]

    Correct Answer: A

    Solution :

    The maximum particle velocity is twice the wave velocity \[a\omega =2\left( \frac{\omega }{k} \right)\] or                \[ak=2\]                                            .... (i) Given    \[y=a\sin 2\pi (bt-cx)\]         or       \[y=a\sin (2\pi bt-2\pi cx)\] The general wave equation                 \[y=a\sin (\omega t-kx)\] then        \[k=2\pi c\] \[\therefore \]  \[a2\pi c=2\]               [From Eq. (i)] or        \[c=\frac{1}{\pi a}\]


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