CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2009

  • question_answer
    A thin prism P of refracting angle\[{{3}^{o}}\]and refractive index 1.5 is combined with another thin prism Q of refractive index 1.6 to produce dispersion without deviation. Then the angle of prism Q is

    A) \[{{3}^{o}}\]                      

    B)         \[{{4}^{o}}\]

    C)  \[{{3.5}^{o}}\]               

    D)         \[{{2.5}^{o}}\]

    E)  \[{{5}^{o}}\]

    Correct Answer: D

    Solution :

    Given refracting angle of prism P \[{{A}_{p}}={{3}^{o}}\] and refractive index of prism P                 \[{{\mu }_{p}}=1.5\] and refractive index of prism Q                 \[{{\mu }_{Q}}=1.6\] \[({{\mu }_{p}}-1){{A}_{p}}=({{\mu }_{Q}}-1){{A}_{Q}}\]                 \[(1.5-1){{3}^{o}}=(1.6-1){{A}_{Q}}\] or            \[0.5\times 3=0.6\times {{A}_{Q}}\] or            \[{{A}_{Q}}=\frac{0.5\times 3}{0.6}\] or            \[{{A}_{Q}}={{2.5}^{o}}\]


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