A) \[{{0.4}^{o}}\]
B) \[{{0.27}^{o}}\]
C) \[{{0.35}^{o}}\]
D) \[{{0.15}^{o}}\]
E) \[{{0.22}^{o}}\]
Correct Answer: D
Solution :
When the apparatus is immersed in water the angular width of a fringe\[\theta =\frac{\lambda }{d}\]and\[\theta ={{0.2}^{o}}\] and the angular width of a fringe in air \[\theta =\frac{\lambda }{d}\] \[\frac{1}{{{\mu }_{w}}}=\frac{\lambda }{\lambda }\] \[\frac{\lambda }{\lambda }=\frac{3}{4}\] Now, \[\frac{\theta }{\theta }=\frac{\lambda }{\lambda }\] \[\theta =\frac{\lambda }{\lambda }\times \theta \] \[\theta =\frac{3}{4}\times {{0.2}^{o}}\] \[\theta =0.15{}^\circ \]
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