A) directly at the target
B) 5 cm below the target
C) 5 cm above the target
D) 2 cm above the target
E) 2 cm below the target
Correct Answer: C
Solution :
Horizontal distance of target is 200 m. Speed of bullet\[=2000\text{ }m{{s}^{-1}}\]. Time taken by bullet to cover the horizontal distance \[t=\frac{200}{2000}=\frac{1}{10}s\] During\[\frac{1}{10}\]s, the bullet will fall down vertically due to gravitational acceleration. Therefore, height above the target, so that the bullet hits the target is \[h=ut+\frac{1}{2}g{{t}^{2}}=\left( 0\times \frac{1}{10} \right)+\frac{1}{2}\times 10\times {{(0.1)}^{2}}\] \[=0.05\,m=5\,cm\]
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