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CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2009

  • question_answer
    Given that \[dE=TdS-pdV\] and\[H=E+pV\]. Which one of the following relations is true?

    A) \[dH=TdS+Vdp\]   

    B) \[dH=SdT+Vdp\]

    C) \[dH=-SdT+Vdp\]           

    D) \[dH=dE+pdV\]

    E) \[dH=dE-TdS\]

    Correct Answer: A

    Solution :

    Given,    \[dE=TdS-pdV\]                              ...(i) \[H=E+pV\]                                        ...(ii) Differentiating Eq. (ii), \[dH=dE+pdV+vdp\]                                      ...(iii) From Eq. (i) and (iii), we get \[dH=TdS+vdp\]


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