A) \[L/4\]
B) \[L/2\]
C) \[(3/2)L\]
D) \[(11/12)L\]
E) \[(5/6)L\]
Correct Answer: D
Solution :
\[{{x}_{1}}=\frac{L}{2}\] \[{{x}_{2}}=L\] \[{{x}_{3}}=L+\frac{L}{4}\] \[{{x}_{3}}=\frac{5L}{4}\] \[\therefore \] \[{{x}_{CM}}=\frac{{{m}_{1}}{{x}_{1}}+{{m}_{2}}{{x}_{2}}+{{m}_{2}}{{x}_{3}}}{3m}\] \[=\frac{\frac{mL}{2}+mL+\frac{m5L}{4}}{3m}\] \[=\frac{11L}{12}\]You need to login to perform this action.
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